3[C-2]=4[C+1]

Solution for 3[C-2]=4[C+1] equation:

Simplifying
3[C + -2] = 4[C + 1]

Reorder the terms:
3[-2 + C] = 4[C + 1]
[-2 * 3 + C * 3] = 4[C + 1]
[-6 + 3C] = 4[C + 1]

Reorder the terms:
-6 + 3C = 4[1 + C]
-6 + 3C = [1 * 4 + C * 4]
-6 + 3C = [4 + 4C]

Solving
-6 + 3C = 4 + 4C

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-4C' to each side of the equation.
-6 + 3C + -4C = 4 + 4C + -4C

Combine like terms: 3C + -4C = -1C
-6 + -1C = 4 + 4C + -4C

Combine like terms: 4C + -4C = 0
-6 + -1C = 4 + 0
-6 + -1C = 4

Add '6' to each side of the equation.
-6 + 6 + -1C = 4 + 6

Combine like terms: -6 + 6 = 0
0 + -1C = 4 + 6
-1C = 4 + 6

Combine like terms: 4 + 6 = 10
-1C = 10

Divide each side by '-1'.
C = -10

Simplifying
C = -10